Comments on: How do I solve this swimming pool word problem? http://goswimmingpool.com/swimming-pool/how-do-i-solve-this-swimming-pool-word-problem/314/ Time to relax in that cooling stretch of water... Thu, 09 Sep 2010 08:46:36 +0000 http://wordpress.org/?v=2.7 hourly 1 By: Ravindra P http://goswimmingpool.com/swimming-pool/how-do-i-solve-this-swimming-pool-word-problem/314/comment-page-1/#comment-730 Ravindra P Sat, 23 Jan 2010 00:00:15 +0000 http://goswimmingpool.com/swimming-pool/how-do-i-solve-this-swimming-pool-word-problem/314/#comment-730 <a href="">Carlotta</a> If it takes x hrs for both pipes to fill, then 1/18 + 1/(x+3) = 1/x => 1/18 = 1/x - 1/(x+3) = 3/(x^2 + 3x) => x^2 + 3x - 54 = 0 => x = 6, x+3 = time by 2nd hose to fill pipe = 9 hrs. Carlotta

If it takes x hrs for both pipes to fill, then
1/18 + 1/(x+3) = 1/x => 1/18 = 1/x - 1/(x+3) = 3/(x^2 + 3x)
=> x^2 + 3x - 54 = 0 => x = 6,
x+3 = time by 2nd hose to fill pipe = 9 hrs.

]]> By: kuroyuli http://goswimmingpool.com/swimming-pool/how-do-i-solve-this-swimming-pool-word-problem/314/comment-page-1/#comment-729 kuroyuli Thu, 21 Jan 2010 03:53:08 +0000 http://goswimmingpool.com/swimming-pool/how-do-i-solve-this-swimming-pool-word-problem/314/#comment-729 <a href="">Corene</a> Define: Total workload = 1 A's productivity = 1/18 B's productivity = b Necessary time to fill by both = x (x+3)b=1 b=1/(x+3) 3b=(1/18)x b=x/54 1/(x+3)=x/54 x(x+3)=54 x=6 b=1/9 Ans. 9 hours Corene

Define:
Total workload = 1
A’s productivity = 1/18
B’s productivity = b
Necessary time to fill by both = x

(x+3)b=1
b=1/(x+3)

3b=(1/18)x
b=x/54

1/(x+3)=x/54
x(x+3)=54
x=6

b=1/9
Ans. 9 hours

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